Foam math
That depends Franklin. Are you talking closed cell or open cell foam. Foam that fills with water (open cell) has almost no buoyant force once it is saturated, it could have negative buoyancy in fact. Closed cell cannot technical "support" weight above water. It has to be submerged in the water to support weight.
Assuming that what you are saying is a block of closed cell foam can displace 60 lb of water just as it is completely submerged we can proceed as follows:
The cube 1'x1'x1' of foam will experience a) the weight suspended below it which I will assume is a point so I don't have to calculate the buoyant force on it and can concentrate on the foam, b) a pressure upward on the bottom of the cube, and c) a pressure downward on the top of the cube.
From above posts the pressure water exerts is:
Pw = x * 62.4 where x is the depth and we are working in fresh water.
I'll assume the foam is not compressible and that it still has the 1'x1'x1' dimensions when submerged to 2'. This is not true at lower depths BTW. The upper surface is at 1.5 ft below the water and the lower surface is at 2.5 ft below the surface so summing forces we get:
Pw on the lower surface times the area of the lower surface - Pw on the upper surface times the upper surface = weight supported.
or
2.5 * 62.4 *1 - 1.5 *62.4 * 1 = W= (2.5-1.5) * 62.4 = 1 *62.4 = 62.4 lb
So the 60 lb point weight the foam block supported when "just submerged" can be increased by 2.4 lb when you push the block's center of buoyancy to 2 ft deep and the block will be at neutral buoyancy.
Back to you Franklin:
If we assume the weight is not a point but a cube 2"x2"x2" and is made of suitable material to make it weight 62.4 lb will the foam block sink or float upward once I mechanically submerge it to 2 ft deep and what weight will have to be added to /subtracted from the weight to achieve neutral buoyancy at 2' if I maintain the 2"x2"x2" size?
That depends Franklin. Are you talking closed cell or open cell foam. Foam that fills with water (open cell) has almost no buoyant force once it is saturated, it could have negative buoyancy in fact. Closed cell cannot technical "support" weight above water. It has to be submerged in the water to support weight.
Assuming that what you are saying is a block of closed cell foam can displace 60 lb of water just as it is completely submerged we can proceed as follows:
The cube 1'x1'x1' of foam will experience a) the weight suspended below it which I will assume is a point so I don't have to calculate the buoyant force on it and can concentrate on the foam, b) a pressure upward on the bottom of the cube, and c) a pressure downward on the top of the cube.
From above posts the pressure water exerts is:
Pw = x * 62.4 where x is the depth and we are working in fresh water.
I'll assume the foam is not compressible and that it still has the 1'x1'x1' dimensions when submerged to 2'. This is not true at lower depths BTW. The upper surface is at 1.5 ft below the water and the lower surface is at 2.5 ft below the surface so summing forces we get:
Pw on the lower surface times the area of the lower surface - Pw on the upper surface times the upper surface = weight supported.
or
2.5 * 62.4 *1 - 1.5 *62.4 * 1 = W= (2.5-1.5) * 62.4 = 1 *62.4 = 62.4 lb
So the 60 lb point weight the foam block supported when "just submerged" can be increased by 2.4 lb when you push the block's center of buoyancy to 2 ft deep and the block will be at neutral buoyancy.
Back to you Franklin:
If we assume the weight is not a point but a cube 2"x2"x2" and is made of suitable material to make it weight 62.4 lb will the foam block sink or float upward once I mechanically submerge it to 2 ft deep and what weight will have to be added to /subtracted from the weight to achieve neutral buoyancy at 2' if I maintain the 2"x2"x2" size?