I’m just trying to wrap my head around how much propane is needed to satisfy the OP’s “top off” requirement.
For lack of better data, let’s us my boat as an example.
Trojan T-125 plus GC batteries x 4 totalling 480Ah (@ a 20hr rate). To get from 50% to 100% SOC will require 240A to be replaced. To do that in 6 hours the charger must output 40A/hr not including any inefficiencies in the charger or battery charge efficiencies or power usage other than the charging of the batteries. Thus no fridge, no radio, no . . .
So the propane generator spec shows that it in conjunction with the boat’s charger would produce approx 13 amps/hr @25% load. And uses 1/3lb of propane to do that. We need 3 times that to satisfy our requirement, thus 75%. So using a straight line fuel consumption we would use 1 lb(of propane)/h for 6 hours for a total of 6 lb of propane to produce the needed 240amps. Seems a reasonable amount. Does the OP normally carry that amount dedicated to charge batteries when needed?
Unfortunately there are many bad assumptions in the above, such as:
- charger is not 100% efficient (more like 80%).
- fuel curves are not linear but . . . well curved. So at 75% load (40A o/p) I would expect more like 2 lbs per hour burn rate rather than 1 lb. Maybe 3lbs per hour
- during the 6 hours of charging other devices will be sharing the output of the charger (generator) with the batteries.
Of course, there is no need to get back to 100% SOC, 90% would be enough.