I'm trying to figure out how much bouancy a 4' diameter hollow sphere creates. If I've got it right, the volume of a sphere equals (4 pi x radius cubed divided by 3 ?) so for a 4' diameter that comes out to 33.5 cubic feet. A cubic foot of seawater weighs 64 lbs. so 33.5 times 64 equals 2144 lbs. Am I correct in assuming that bouancy equals weight of the water displaced? If so, would the bouancy of a 4' diameter sphere be 2144 lbs. minus the weight of the sphere? Any help or insight would be greatly appreciated!