Just a follow up regarding will wire burn up in a lightning strike.. lots of details.. but I guess I need to back up what I said..
First, the equation I'm using is delta temp * mass * specific heat
is equal to
Power * time or I*2 * R * time
This assumes that all the energy into the volume stays in the volume because of the short time frame (ie, none of the heat generated exits the volume)
The total equation for temperature change is then:
delta Temp = I**2 * R * delta time / ( mass * C )
Mass = density * volume = density * area * length
For copper, density = 8.8e3 kg/m**3
C = 287 J/Kg*C = specific heat of copper
Delta time assumed is 7e-4 seconds (summation of a bunch of 2 usec pulses over a much longer time frame)
For a "typical" 30KA peak current lightning strike, the temperature rise in one meter of wire is
gauge / resistance / mass / temperature rise in C
----------------------------------------------------------------------
10 / 3.3e-3 / 4.63e-2 / 158 C
8 / 2.1e-3 / 7.35e-2 / 99.6 C
6 / 1.32e-3 / 1.16e-1 / 25.0 C
4 / 8.31e-4 / 1.85e-1 / 9.84 C
2 / 5.22e-4 / 2.94e-1 / 3.90 C
The last column "delta T in C" is the temperature change in Celsius due to the power deposited in the wire.
For much stronger strike of 100 K amps,
gauge / resistance / mass / temperature rise in C
----------------------------------------------------------------------
10 / 3.3e-3 / 4.63e-2 / 1750 C
8 / 2.1e-3 / 7.35e-2 / 1110 C
6 / 1.32e-3 / 1.16e-1 / 278 C
4 / 8.31e-4 / 1.85e-1 / 109 C
2 / 5.22e-4 / 2.94e-1 / 43.3 C
Note that the temperature rise in the wire does not depend on the lenght. Longer wire will have larger volume/mass so you end up with the same temp rise no matter what lenght.
If you believe the numbers (I have no reason not to)... for a 30KA lightning current, the temperature rise in even 10 gauge wire is only 158 C. Copper melts at 1084.6 C.. so no problem.
For the much stronger 100KA lightning current, you can see that 8 gauge wire has increased temp by 1110 C - ie, its melted. But 4 gauge wire has only increased in temp by 109 C - not much at all.
Other than digging through text books, here is the only place I can find a reference on the method used.
http://www.eng-tips.com/viewthread.cfm?qid=253435&page=1
The time of 7e-4 seconds comes from an assumption that there are about 350 pulses over 35 msec and each pulse lasts 2 usec. 350 pulse * 2 usec = 7e-4 second (from some reference I will find is someone REALLY wants to know).