I suspect by now we have lost
@GeneraiT001, the OP. To get back to his question...
There are 2 sides to the equation, charging and usage. The goal is to charge capacity and usage be equal.
To determine battery needs:
- Estimate daily consumption when sailing and at anchor.
- Decide on the number of days of electrical power is needed assuming no charging, or how long can the battery bank go without charging?
The answers to those questions will determine battery size. For instance, if electrical consumption is 120ah per day while sailing and the interval between charging is 3 days, the battery bank will need to be 3 * 120 =360 ah of usable battery capacity. With lead acid that means about 720 ah and for LFP about 400 ah. At anchor, the draw will be less, so the charge interval can be longer.
Charging capacity:
In this example, every three days it is necessary to return 360ah plus 15% for efficiency costs to the batteries. Using Calder's estimate of daily solar output to be 3 times the panel's nominal output the panel size can be estimated. First change the amphours to watt-hours by multiplying ah by voltage, the 360ah is equal to 4,320 wh. Divide by 3 to get panel size. For this example the panel size would need to be about 1,500 watts.
It works about the same with determining alternator size. A safe charge rate for LFP batteries will be around .5C, which would require a 200 amp alternator capable of producing 200 amps for about 2 hours of engine run time. Unless the engine room is exceptionally well ventilated to keep the alternator cool, a more realistic estimate of output would be closer to 100 amps.
Once you get your head wrapped around these basic hypothetical issues, you can begin to bring the numbers in to real life situations. Dealing with the limitations of the boat, your wallet, and what actually happens with sailing.
When are you planning to leave on your journey to the Azores and Israel?