We were out on moorings adjacent to friends on a 2006 H41 last night when I got a call from them to see if I could bring over my start battery as theirs was dead and they could not get the engine nor the generator started. Their house bank appeared to be fine but we could not come up with a means short of jumper cables to line up the house battery to the starter.
I've got the exact same configuration on my boat and was wondering if anyone could verify my understanding of the circuit. (SEE ATTACHED SCHEMATIC). Each battery has its own selector switch with an on/off position. It appears to me that the house and the starting batteries are cross connected via the Cole Hersee solenoid, which is designed to be normally energized. I assume that the solenoid remains energized as long as the start battery voltage is above the drop out voltage for the solenoid. Once the voltage in the start battery decreases the solenoid deenergizes isolating the house battery from the start battery. Once that happens there is no way to switch the house bank over to start the engine. Does this make sense?
If so I'm not sure why we didn't have sufficien voltage in the starting battery to start the engine short of a catastrophic failure of the starting battery which may have been the case.
Ultimately we disconnected his start battery and used mine to get the Yanmar started. We disconnected my good battery and the Yanmar as expected continued to run and he was able to get back to the marina.
Just want to make sure we did not miss anything.
Thanks
Marc
I've got the exact same configuration on my boat and was wondering if anyone could verify my understanding of the circuit. (SEE ATTACHED SCHEMATIC). Each battery has its own selector switch with an on/off position. It appears to me that the house and the starting batteries are cross connected via the Cole Hersee solenoid, which is designed to be normally energized. I assume that the solenoid remains energized as long as the start battery voltage is above the drop out voltage for the solenoid. Once the voltage in the start battery decreases the solenoid deenergizes isolating the house battery from the start battery. Once that happens there is no way to switch the house bank over to start the engine. Does this make sense?
Ultimately we disconnected his start battery and used mine to get the Yanmar started. We disconnected my good battery and the Yanmar as expected continued to run and he was able to get back to the marina.
Just want to make sure we did not miss anything.
Thanks
Marc
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