Exhaust 'size' is calculated based on 'displacement volume' per unit time. cc's or cubic inches per minute, etc. This is to keep the 'velocity' below certain limits to prevent 'resonance', increase the 'noise', and lessen 'back-pressure', etc. ... a 'pressure drop' calculation.
A correlation is possible - Assume that the 2" exhaust 'size' corresponds to max. rpm (volumetric capacity at MAX rpm or per minute). Select or estimate the normal rpm during 'normal' power generation then multiply the 2" Ø 'cross sectional' area (3.14 in sq.) by the ratio of: operating rpm divided by MAX rpm .... and that will give you the 'cross sectional' area of 'piping' required for operation at 'normal' rpm.
Of course you can lessen the diameter if the engine is not running 'full out', but that should be accompanied with the MINIMUM usage of elbows, especially close radiused 90 deg. elbows, and other 'transition fittings' that cause velocity increase/decrease, etc. ... 'tight bends', or anyother component that makes the fluid to 'turn a corner', etc. cause high pressure drop in fluidic mass transfer systems - avoid them. Dont be an anal fanatic 'neatnik' by putting in unnecessary elbows, fittings, etc. etc.
Inotherword if you reduce the diameter of the 'hosing, etc.' be sure to only employ loooong radiused elbows, etc. and keep the 'numbers' of hose components (nipples, unions, etc. etc. etc.) to an absolute bare minimum. Also make the exhaust 'run' as 'short as possible'.
;-)