Things to consider...
The brightest 5mm LEDs have a 15° beam off their end at the 1/2 brightness points. That means you need 14 LEDs, 7 each for red and green to cover the 225° forward, another 14 LEDs for the steaming light, and 8 or 9 LEDs to cover the 135° of the stern light. Sure, there are LEDs with wider 1/2 power point angles, but they are usually much dimmer.An anchor light would need 24 LEDs arranged in a circle, or one of those 350mA Luxeon side-emitters mounted upside down in the lens.The problem with cheap LED replacement lights is that they don't use current regulation, only a ballast resistor. And to compound this problem, sometimes manufacturers put as many LEDs as they can get in series with a ballast resistor to reduce the current draw of their lamp. This makes them overly sensitive to the voltage variance found in a boat. For example, a single 3.5 volt LED set up for no more than 20mA with the 14.5V of an outboard would call for 14.5V minus 3.5V equals 11V divided by 0.020 amps equals 550 ohms of resistance. If you used that much resistance, when the outboard WASN'T running, and the battery charged at 12.5V, that only leaves 12.5V minus 3.5V equals 9V across the resistor divided by 550 ohms equals only 16mA running through the LED and a little dimmer light. If the battery is half discharged at 11.5V that's now 8V/550=14.5mA and an even dimmer LED.To light up three of these LEDs, each with their own resistor, uses 60mA at 14.5V Since these LEDs drop 3.5V each, some manufacturers string two or three of them in series with each resistor and get 2-3 times the light for the current of one LED. If we go back to calculate the ballast resistor for three 3.5V LEDs in series sharing 20mA at 14.5V charging voltage, we get 14.5V - 10.5V = 4 volts divided by 20mA equals 200 ohms. The problem occurs when we shut down the outboard and have 12.5V of a charged battery, leaving only 2V across the resistor. Now we have 1/2 the current or about 10mA through the LEDs, dimming them signficantly. It gets even worse at the 11.5V of a half discharge battery, where we only have 1V across the resistor and less than 5mA going through the LEDs.This isn't much of a problem in a motor vehicle with the engine running all the time. But it's a significant problem for sailboats, and even powerboats at anchor. The solution is to use a 32 cent regulator chip, something like the LM317Z with a 62 ohm resistor, in series with 2 3.5V LEDs. This is a good compromise on power savings and will keep the LEDs at maximum brightness all the way down to about 9V when cranking the outboard. Comparing a 6 LED setup, the one LED per resistor uses 120mA, the 3 LED per resistor uses 40mA, and the two LED per regulator chip and resistor uses 60mA.Even if you find a fixture that mounts these replacement lights vertically rather than horizontally, shining on the bulkhead, LEDs are like having little spotlights in the cabin. The reason they use less power than the incandescent is that they only light up a tiny cone of the almost sphere (except for the base) an incandescent does. Some people like a dark cabin with little spotlights, others prefer even illumination. The closest you'll get to the latter, without making a disco-ball of 5mm LEDs, is with the Luxeon LEDs.